我试图从给定XML文件中的特定元素中找到给定XML元素的相对深度,我尝试使用XPATH,但是我对XML解析不是很熟悉,也没有得到理想的结果.我还需要在计数时忽略数据元素.
下面是我编写的代码和示例XML文件.
例如. TS837_2000A_Loop元素中NM109_BillingProviderIdentifier的深度为4.
父节点是:TS837_2000A_Loop< NM1_SubLoop_2< TS837_2010AA_Loop< NM1_BillingProviderName
因为NM109_BillingProviderIdentifier是NM1_BillingProviderName的子级,因此从TS837_2000A_Loop到NM1_BillingProviderName的相对深度为4(包括TS837_2000A_Loop).
package com.xmlexamples;
import java.io.File;
import java.io.FileInputStream;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Document;
public class XmlParser {
public static void main(String[] args) throws Exception {
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
dbf.setValidating(false);
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(new FileInputStream(new File("D://sample.xml")));
XPathFactory factory = XPathFactory.newInstance();
XPath xpath = factory.newXPath();
String expression;
expression = "count(NM109_BillingProviderIdentifier/preceding-sibling::TS837_2000A_Loop)+1";
Double d = (Double) xpath.compile(expression).evaluate(doc, XPathConstants.NUMBER);
System.out.println("position from TS837_2000A_Loop " + d);
}
}
<?xml version='1.0' encoding='UTF-8'?>
<X12_00501_837_P xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<TS837_2000A_Loop>
<NM1_SubLoop_2>
<TS837_2010AA_Loop>
<NM1_BillingProviderName>
<NM103_BillingProviderLastorOrganizationalName>VNA of Cape Cod</NM103_BillingProviderLastorOrganizationalName>
<NM109_BillingProviderIdentifier>1487651915</NM109_BillingProviderIdentifier>
</NM1_BillingProviderName>
<N3_BillingProviderAddress>
<N301_BillingProviderAddressLine>8669 norTHWEST 36TH ST </N301_BillingProviderAddressLine>
</N3_BillingProviderAddress>
</TS837_2010AA_Loop>
</NM1_SubLoop_2>
</TS837_2000A_Loop>
</X12_00501_837_P>
解决方法:
获取任何节点深度的关键方法是计算其祖先(包括父节点,父节点的父节点等):
count(NM109_BillingProviderIdentifier/ancestor-or-self::*)
这将使您计数到根.要获取相对计数,即从根以外的任何位置获取相对计数,假设名称不重叠,则可以执行以下操作:
count(NM109_BillingProviderIdentifier/ancestor-or-self::*)
- count(NM109_BillingProviderIdentifier/ancestor::TS837_2000A_Loop/ancestor::*)
根据是将电流还是基础元素包括在计数中,请使用“祖先或自身”或“祖先”轴.
PS:您可能应该感谢Pietro Saccardi如此慷慨地使您的帖子和庞大的XML(一行上有4kB ..)示例XML可读.
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