我有这个XML响应:http://jsfiddle.net/ZeeHv/
我正在尝试使用转储中的信息创建这样的东西:
<UL>
<li>Academic
<ul>
<li>BM</li>
<li>CMTTE</LI>
<li>DM</li>
<li>PM</li>
</ul>
</li>
</ul>
<ul>
<li>ARCHIVE</li>
</UL>
<ul>
<LI>ASSOCIATIONS
<ul>
<li>BM</li>
<li>DM</LI>
<li>PM</li>
</ul>
</LI>
</ul>
最后,XML可以为我提供所有站点和子站的列表:
https://hosted.demo.ca
https://hosted.demo.ca/academic
https://hosted.demo.ca/academic/bm
https://hosted.demo.ca/academic/cmtte
https://hosted.demo.ca/academic/dm
https://hosted.demo.ca/academic/pm
https://hosted.demo.ca/archive
https://hosted.demo.ca/associations
https://hosted.demo.ca/associations/bm
https://hosted.demo.ca/associations/dm
https://hosted.demo.ca/associations/pm
JS用来获取XML:
function getAllSites(){
$().SPServices({
operation: "GetAllSubWebCollection",
async: true,
completefunc: function(xData, Status){
$(xData.responseXML).find("Web").each(function(){
console.log($(this).attr("Url"));
});
}
});
}
解决方法:
一个简单的解决方案是根据链接的深度构建索引图,深度由URL中的/数确定.
var map = {}; //init the map
for (var i = 0, l = webs.length; i < l; i++) {
//we create a index for our links based on the depth of them by `/`
var m = webs[i].attributes['Url'].value.substring(23, webs[i].attributes['Url'].value.length).split('/').length;
map[m] = map[m] || []; //make sure we leave alone the old values if there is none init with new array
map[m].push(webs[i].attributes['Url'].value); //push new value to node
}
console.log(map);
的console.log(地图);将输出类似于此的对象:
{
"1": ["https://hosted.demo.ca", "https://hosted.demo.ca/academic", "https://hosted.demo.ca/archive", ...],
"2": ["https://hosted.demo.ca/academic/bm", "https://hosted.demo.ca/academic/cmtte", ...],
}
从中您可以创建元素列表.
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