<Customers>
<Customer CustomerID="alc">Alice</Customer>
</Customer>
和
<Orders>
<Order OrderID="001" CID="alc">apple</Order>
</Orders>
现在我需要加入这两个XML文件并使用内部联接创建一个新文件:
<Result>
<Join>
<Customer CustomerID="alc">Alice</Customer>
<Order OrderID="001" CID="alc">apple</Order>
</Join>
</Result>
我有这个问题:
var result = new XElement("Result",
from customer in XElement.Load("Customers.xml").Elements("Customer")
join order in XElement.Load("Orders.xml").Elements("Order")
on
(string)customer.Attribute("CustomerID")
equals
(string)order.Attribute("CID")
select new XElement("Join",
new XElement("Customer", (string)customer.Element("Customer"),
new XAttribute("CustomerID", (string)customer.Attribute("CustomerID"))),
new XElement("Order", (string)order.Element("Order"),
new XAttribute("OrderID", (string)order.Attribute("OrderID")),
new XAttribute("CID", (string)order.Attribute("CID")))));
result.Save("result.xml");
有了这个我无法获得数据“爱丽丝”和“苹果”.结果是这样的:
<Result>
<Join>
<Customer CustomerID="alc" />
<Order OrderID="001" CID="alc" />
</Join>
</Result>
我想也许(字符串)customer.Element(“Customer”)和(字符串)order.Element(“Order”)有一些问题,我不知道如何修改它们.
解决方法:
您只需cast an element to a string
即可获得其文本值:
select new XElement("Join",
new XElement("Customer", (string)customer,
new XAttribute("CustomerID", (string)customer.Attribute("CustomerID"))),
new XElement("Order", (string)order,
new XAttribute("OrderID", (string)order.Attribute("OrderID")),
new XAttribute("CID", (string)order.Attribute("CID")))));
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。