c# – 解析多个子节点的xml和连接结果

我需要解析一个xml文件,需要加入节点’driver’的结果.每个’品牌’节点都是唯一的.样本xm​​l文件：

<brand name = "ford">   
   <transport category="car">
      <driver name="John, Doe"/>
      <driver name="Jane, Doe"/>
    </transport>
</brand>
<brand name = "opel">
   <transport category="car">
      <driver name="Jerry, Smith"/>
      <driver name="Jeff, Perry"/>
     </transport>
</brand>

预期结果：

John, Doe - Jane, Doe
Jerry, Smith - Jeff, Perry

我的代码到目前为止：

    XmlTextReader reader = new XmlTextReader(@"D:\myfile.xml");

    while (reader.Read())
    {
        if (reader.Name == "brand")
            {
                XmlReader inner =  reader.ReadSubtree();
                while (inner.Read()) ;

                if (reader.Name == "driver")
                {
                    string drvNames = reader.GetAttribute("name");
                }   
            }
    }

我无法得到’司机’的结果.有一个或多个’驱动’节点.语言C#

解决方法:

你可以使用Linq到Xml：

var xdoc = XDocument.Load(@"D:\myfile.xml");
var query = from t in xdoc.Descendants("transport")
            select String.Join(" - ", t.Elements("driver")
                                      .Select(e => (string)e.Attribute("name")));

如果无法将整个文件加载到内存中：

XmlTextReader reader = new XmlTextReader(@"D:\myfile.xml");
List<string> result = new List<string>();

while (reader.Read())
{    
    if (reader.Name == "brand")
    {
        XmlReader inner = reader.ReadSubtree();
        List<string> names = new List<string>();

        while (inner.Read())
        {
            if (reader.Name == "driver")
                names.Add(reader.GetAttribute("name"));
        }

        if (names.Any())
            result.Add(String.Join(" - ", names));
    }
}