将XML数据分解为SQL行时保留元素顺序

在将 XML分解为sql Server视图中的行时,如何返回元素序列？

样本输入：

<ol>
  <li>Smith</li>
  <li>Jones</li>
  <li>brown</li>
</ol>

期望的输出：

Sequence  Name
--------  -----------
    1     Smith
    2     Jones
    3     brown

现有观点：

CREATE VIEW OrderedList
AS
SELECT [Sequence] = CAST(NULL AS int)   -- Todo: Get ordinal position
       [Name] = b.b.value('.','nvarchar(max)')
FROM
(
    SELECT a = CAST('<ol><li>Smith</li><li>Jones</li><li>brown</li></ol>' AS xml)
) a
CROSS APPLY a.a.nodes('/ol/li') b (b)

您可以在xml节点上使用row_number().

CREATE VIEW OrderedList
AS
SELECT [Sequence] = ROW_NUMBER() OVER(ORDER BY b.b),[Name] = b.b.value('.','nvarchar(max)')
FROM
(
    SELECT a = CAST('<ol><li>Smith</li><li>Jones</li><li>brown</li></ol>' AS xml)
) a
CROSS APPLY a.a.nodes('/ol/li') b (b)

参考：Uniquely Identifying XML Nodes with DENSE_RANK 由Adam Machanic.