在Grails中将xml转换为域对象

我是一个有趣的项目的grails新手.我正在序列化这样一个类：

def msg = (listing as XML).toString()

尝试使用XMLSlurper反序列化类,如下所示：

def root = new XmlSlurper().parseText(listingString)
def sellerNode = root.seller

我正在尝试重建这个对象：

Listing{

    Date dateCreated
        String description
        Date endDateTime
        String name
        Float startingPrice
        Customer winner
        static hasMany = [bids: Bid] // B-4
        static belongsTo = [seller: Customer]
    }

}

从这个xml：

<?xml version="1.0" encoding="UTF-8"?>
<listing>
    <bids>
        <bid>
            <amount>10.5</amount>
            <bidder>
                <accountExpired>false</accountExpired>
                <accountLocked>false</accountLocked>
                <dateCreated/>
                <emailAddress>[e-mail]</emailAddress>
                <enabled>false</enabled>
                <password>secret</password>
                <passwordExpired>false</passwordExpired>
                <username>validguy</username>
            </bidder>
            <dateCreated>2012-04-08 21:16:41.423 CDT</dateCreated>
            <listing/>
        </bid>
        <bid>
            <amount>10.0</amount>
            <bidder>
                <accountExpired>false</accountExpired>
                <accountLocked>false</accountLocked>
                <dateCreated/>
                <emailAddress>[e-mail]</emailAddress>
                <enabled>false</enabled>
                <password>secret</password>
                <passwordExpired>false</passwordExpired>
                <username>validguy</username>
            </bidder>
            <dateCreated>2012-04-08 21:16:41.415 CDT</dateCreated>
            <listing/>
        </bid>
    </bids>
    <dateCreated/>
    <description>A test listing</description>
    <endDateTime>2012-04-09 21:16:41.407 CDT</endDateTime>
    <name>Default</name>
    <seller>
        <accountExpired>false</accountExpired>
        <accountLocked>false</accountLocked>
        <dateCreated/>
        <emailAddress>[e-mail]</emailAddress>
        <enabled>false</enabled>
        <password>secret</password>
        <passwordExpired>false</passwordExpired>
        <username>validguy</username>
    </seller>
    <startingPrice>10.0</startingPrice>
    <wasNotificationSent>false</wasNotificationSent>
    <winner>
        <accountExpired>false</accountExpired>
        <accountLocked>false</accountLocked>
        <dateCreated/>
        <emailAddress>[e-mail]</emailAddress>
        <enabled>false</enabled>
        <password>secret</password>
        <passwordExpired>false</passwordExpired>
        <username>validguy</username>
    </winner>
</listing>

首先,我遇到了解决每个节点值的问题.我已经尝试过def卖家=新客户(名称：sellerNode.@ username),但这不起作用,因为我认为@username需要是属性而不是元素.
其次,我必须“手动”解析这个xml吗？是不是有更好的方法来自动反序列化这个xml？

我已经看了几个帖子,包括这个帖子：Import XML into a Grails Domain Class然而你可以看到,我的xml没有像这篇文章中的xml这样的属性.

谢谢,

解决方法

如果XML的源是Web请求,则可以将parseRequest：true添加到控制器的UrlMapping,grails将自动解析XML请求. XML将以params的形式呈现,您可以像任何其他请求一样进行数据绑定.

如果您从其他源获取XML,请查看类XMLParsingParameterCreationListener.groovy中的XML到参数映射转换.