I want to parse a xml string that is a web service response sent from servier,the xml looks like this:
<?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <soap:Body> <addResponse xmlns="http://tempuri.org/"> <addResult>20</addResult> </addResponse> </soap:Body> </soap:Envelope>
我想在元素addResult之间获得值20.我的plsql代码段如下所示:
declare v_xml clob; begin v_xml := '<?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <soap:Body> <addResponse xmlns="http://tempuri.org/"> <addResult>20</addResult> </addResponse> </soap:Body> </soap:Envelope>'; for c in (select results from xmltable('Envelope/Body/addResponse' passing xmltype(v_xml) columns results varchar(100) path './addResult') ) loop dbms_output.put_line('the result of calculation is : ' || c.results); end loop; end;
seems that nothing was printed out,but if I remove the namespace ‘soap’,the code works well,so can anybody tell me how can I got the value 20 when the xml has namespace?
解决方法
基于
this answer
应该是这样的:
declare v_xml clob; begin v_xml := '<?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <soap:Body> <addResponse xmlns="http://tempuri.org/"> <addResult>20</addResult> </addResponse> </soap:Body> </soap:Envelope>'; for c in (select results from xmltable(xmlnamespaces(default 'http://tempuri.org/','http://schemas.xmlsoap.org/soap/envelope/' as "soap" ),'soap:Envelope/soap:Body/addResponse' passing xmltype(v_xml) columns results varchar(100) path './addResult')) loop dbms_output.put_line('the result of calculation is : ' || c.results); end loop; end;
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