我需要创建如下所示的
XML：
<record id="100000000000000000" type="Message">
...a bunch of xml ...
</record>
相反,使用我正在使用的FSsharp代码,我得到了这个：
<record>
<type>Message</type>
<id>118448</id>
...a bunch of xml....
</record>
这是我目前正在做的事情：
type record( id:int,sr:sender,recipients: recipient array,atts : attachment array,con : conversation,madeDate : creation) =
let mutable id: int = id
let mutable typ = "Message"
let mutable creation = madeDate
let mutable sender = sr
let mutable recipients = recipients
let mutable conversation = con
let mutable attachments = atts
public new() =
record( -1,sender(-1,"Joe","Plumber","Joe@plumber.com"),Array.empty,conversation(),creation())
[<XmlElement("type")>]
member this.Type with get() = typ and set v = typ <- v
[<XmlElementAttribute("id")>]
member this.Id with get() = id and set v = id <- v
[<XmlElement("creation")>]
member this.Creation with get() = creation and set v = creation <- v
[<XmlElement("sender")>]
member this.Sender with get() = sender and set v = sender <- v
[<XmlArrayAttribute("recipients")>]
[<XmlArrayItem(typeof<recipient>,ElementName = "recipient")>]
member this.Recipients with get() = recipients and set v = recipients <- v
[<XmlElement("conversation_info")>]
member this.Conversation with get() = conversation and set v = conversation <- v
[<XmlArrayAttribute("attachments")>]
[<XmlArrayItem(typeof<attachment>,ElementName = "attachment")>]
member this.Attachments with get() = attachments and set v = attachments <- v
解决方法
我想你想要XmlAttributeAttribute而不是XmlElementAttribute.
注意
[<XmlElement>]
和
[<XmlElementAttribute>]
是一回事(就像C#一样).
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