xml – XQuery – 分组和计数

这是我的 XML文件的结构 –

<A>
  <Name t="Mr.">James Bond</Name>
  <Name t="Mr.">Allen Bond</Name>
  <Name t="Mr." p="X">James Bond</Name>
  <Name t="Mr." p="X">James Bond</Name>
  <Name t="Mr.">James Bond</Name>
  <Name t="Mrs.">James Bond</Name>
  <Name t="Mrs.">James Bond</Name>
  <Name t="Mr.">James Bond</Name>
  <Name t="Mrs." p="Y">James Bond</Name>
  <Name t="Mrs." p="Y">James Bond</Name>
</A>

我期待的输出是 –

<A>
  <N>Allen Bond Mr - 1</N>
  <N>James Bond Mr - 3</N>
  <N>James Bond Mr,X - 2</N>
  <N>James Bond Mrs - 2</N>  
  <N>James Bond Mrs,Y - 2</N>
</A>

我能够得到不同的名字,但不能添加计数…

解决方法

带有 group by的XQuery 3.0解决方案：

<A>{
  for $name in //Name
  let $full :=
    if(not($name/@p)) then concat($name,' ',$name/@t)
    else concat($name,$name/@t,',$name/@p)
  group by $full
  return <N>{$full,'-',count($name)}</N>
}</A>

与distinct-values($arg)的XQuery 1.0解决方案：

<A>{
  let $names :=
    for $name in //Name
    return if(not($name/@p)) then concat($name,$name/@p)
  for $name in distinct-values($names)
  return <N>{$name,count($names[. eq $name])}</N>
}</A>