【数据结构】 利用栈求解 括号匹配问题

括号是否匹配问题求解

以下为代码演示：

/***
// 括号匹配问题
InitStack ( &S)  :  栈的初始化
Push ( &S,e) :进栈
Pop (&S ) : 出栈
GetTop (S ): 取栈顶元素
IsEmpty (S): 判栈空否
***/
#include <stdio.h>
#include <stdlib.h>

#define STACK_MAX 1000
typedef char ElemType;

typedef struct Stack
{
	int top;
	ElemType elem[STACK_MAX];
}Stack,*Pstack;

void InitStack (Pstack S) ;           // 栈的初始化
void Push (Pstack S,ElemType elem) ;  // 进栈
void Pop (Pstack S ) ;                // 出栈
ElemType GetTop (Pstack S );          // 取栈顶元素
bool IsEmpty (Pstack S);              // 判栈空否
bool match(char a,char b);

void main()
{
	int i = 0;
	bool bMatch = true;
	char s[100] = "";
	scanf("%s",s);

	Stack data;
	Pstack S = &data;

	InitStack(S);

	while (s[i] != '\0')
	{
		char elem = s[i];

		if (elem == '{' || elem == '[' || elem == '(')
			Push(S,elem);
		else
		{
			if (IsEmpty(S))
			{
				bMatch = false;
				break;
			}

			if (match(elem,GetTop(S)))
			{
				Pop(S);
			}
			else
			{
				bMatch = false;
				break;
			}
		}
		i++;
	}

	if (bMatch && IsEmpty(S))
	{
		printf("括号匹配\n");
	}
	else
	{
		printf("括号不匹配\n");
	}
}


bool match(char a,char b)
{
	switch(a)
	{
	case '}':
		if (b == '{')
			return true;
	case ']':
		if (b == '[')
			return true;
	case ')':
		if (b == '(')
			return true;
		break;
	default :
		exit(-1);
	}
}
void InitStack (Pstack S)   // 栈的初始化
{
	S->top = 0;

	for (int i = 0; i < STACK_MAX; i++)
		S->elem[i] = 0;
}

void Push (Pstack S,ElemType elem) // 进栈
{
	if (S->top != STACK_MAX)    // 判断是否栈满
		S->elem[(S->top)++] = elem;
}

void Pop (Pstack S ) // 栈顶元素出栈
{
	S->elem[-- (S->top)] = 0;
}

ElemType GetTop (Pstack S ) // 取栈顶元素
{
	if (!IsEmpty(S))
		return S->elem[S->top-1];
	else
		printf("栈空~~\n");
}

bool IsEmpty (Pstack S) // 判栈空否
{
	return (S->top == 0);
}