如何解决声明int的数组
| 这两个声明之间有什么区别吗？int x[10];
int* x = new int[10];
解决方法
#include<iostream>
int y[10];
void doSomething()
{
int x[10];
int *z = new int[10];
//Do something interesting
delete []z;
}
int main()
{
doSomething();
}
int x[10];
doSomething()
int y[10];
int *z = new int[10];
delete[] z;
int x[10];
int* x = new int[10];
int*
int* b = x; // Either form of x will work
void foo(int* p) {}
foo(x); // Either form will work
int*
delete [] x; // UB for the first case,necessary for the second case.
sizeof(x) == sizeof(int)*10 // First case
sizeof(x) == sizeof(int*) // Second case.
int (*)[10]
&x
int**
void foo(int (&arr)[10]) { }
x
x
foo(x); // OK for first case,not OK for second case.
10
int
delete [] x;
int x[10];
void method() {
int y[10];
int *z = new int[10];
delete z;
}
int x[10]
int y[10]
new[]
&x
&z
&x
int (*)[10]
&z
int **
int x[10];
x
10
int* x = new int[10];
x
int
int
x[i]
i
0
9
&x[i]
*(x+i)
x[i]
0
9
i
sizeof
sizeof(x)
sizeof(int)
sizeof(x)/sizeof(*x)
10
x
{
int x[10];
} // x and all its elements cease to exist here
x
new x[10]
// x as previously defined in one or the other form
int y[10];
int z;
x = y;
x = &z;
x
y
x
new int [10]
x
x
int x[10]
int* x = new int[10];
void doSomething(int size)
{
int x[size]; // does not compile
int *z = new int[size];
//Do something interesting ...
doMore(z,size);
}
void doMore(int anArray[],int size)
{
// ...
}
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