如何插入数据库mysql解决？

如何解决如何插入数据库mysql解决？

如何将文件数据插入到mysql表中？

代码：

import pymysql.cursors
import pymysql as MySQLdb
import pymysql
from Bio import SeqIO

try:
    conexao = MySQLdb.connect(host="localhost",user="root",passwd="xxx",db="db_teste")
    print("conectado")
    print(conexao)
except:
    print("Não conectado")


for item in SeqIO.parse('seqteste.txt','fasta'):
    dados = print('>{}\t{}'.format(str(item.description).replace('|','\t'),item.seq),)
    with conexao:
         with conexao.cursor() as cursor:
            sql =  "INSERT INTO `tabelateste` (`id`,`id_name`,`host`,`organism`,`seq`) VALUES(1,%s,%s)"
            cursor.execute(sql,(dados,dados,))
            conexao.commit()

错误：

pymysql.err.OperationalError: (1136,"Column count doesn't match value count at row 1")

我们的：

sql =  "INSERT INTO `tabelateste` (`id`,`seq`) VALUES(%s,dados))
            conexao.commit()

error:

    line 125,in mogrify
        query = query % self._escape_args(args,conn)
    TypeError: not enough arguments for format string

如何解决这个错误并且能够在mysqldb表中插入数据？

我的序列：

>gb:KX262887|Organism:Zika virus|Strain Name:103451|Segment:null|Subtype:Asian|Host:Human
GTTGTTGATCTGTGTGAATCAGACTGCGACAGTTCGAGTTTGAAGCGAAAGCTAGCAACAGTATCAACAG
GTTTTATTTTGGATTTGGAAACGAGAGTTTCTGGTCATGAAAAACCCAAAAAAGAAATCCGGAGGATTCC

>gb:KX262887|Organism:Zika virus|Strain Name:103451|Segment:null|Subtype:Asian|Host:Human
    GTTGTTGATCTGTGTGAATCAGACTGCGACAGTTCGAGTTTGAAGCGAAAGCTAGCAACAGTATCAACAG
    GTTTTATTTTGGATTTGGAAACGAGAGTTTCTGGTCATGAAAAACCCAAAAAAGAAATCCGGAGGATTCC

>gb:KX262887|Organism:Zika virus|Strain Name:103451|Segment:null|Subtype:Asian|Host:Human
    GTTGTTGATCTGTGTGAATCAGACTGCGACAGTTCGAGTTTGAAGCGAAAGCTAGCAACAGTATCAACAG
    GTTTTATTTTGGATTTGGAAACGAGAGTTTCTGGTCATGAAAAACCCAAAAAAGAAATCCGGAGGATTCC

预期退出输出：

mysqldb

id  id_name            host        organism         seq
1   gb:KX262887        Human       Zika Virus       aatgtgttt

解决了吗？

解决方法

您必须仔细匹配列、占位符和值，以便每个列都有一个相同的编号：

sql =  "INSERT INTO `tabelateste` (`id`,`id_name`,`host`,`organism`,`seq`) VALUES(%s,%s,%s)"
            cursor.execute(sql,(dados,dados,dados))
            conexao.commit()

注意现在如何在元组中指定 5 个列、5 个占位符和 5 个绑定。你有一个额外的 %s。

概念上你想做的是：

(column_name,...) <-- Columns specified
     |
     v
(   %s,... ) <-- Placeholders specified
     |
     v
(bind_value,... ) <-- Binding on execute()

请注意，这些必须完全以 1:1:1 的比例相关。任何不匹配都会导致您看到的错误。

,

改变：

for item in SeqIO.parse('seqteste.txt','fasta'):
    dados = print('>{}\t{}'.format(str(item.description).replace('|','\t'),item.seq),)

进入

import re

cnt = 0
for item in SeqIO.parse('seqteste.txt','fasta'):
    cnt += 1
    s=(str((item.description).strip('')))
    pattern_id = "(.*?)\|Organism"
    pattern_host = "Host:(.*.)"
    pattern_org = "Organism:(.*?)\|Strain"
    ids= re.search(pattern_id,s).group(1)
    host = re.search(pattern_host,s).group(1)
    org = re.search(pattern_org,s).group(1)
    dados = [str(cnt),ids,host,org,str(item.seq)]

和：

 cursor.execute(sql,dados))

与：

cursor.execute(sql,(dados[0],dados[1],dados[2],dados[3],dados[4]))

让我知道它的行为，我没有你的数据库，无法测试我的代码