对象映射器在将对象转换为字符串 Java 时删除空值和空值

如何解决对象映射器在将对象转换为字符串 Java 时删除空值和空值

响应 api 调用，我发送 Json 类对象作为响应。

我需要这样的响应，而不需要删除空对象。

{
   "links": {
      "products": [],"packages": []
    },"embedded":{
      "products": [],"packages": []
    }
}

但最终的响应看起来像这样

{
 "links": {},"embedded": {}
}

解决方法

需要注意的两点：

1. null 和 empty 是不同的东西。
2. AFAIK Jackson 配置为默认使用 null 值序列化属性。

确保正确初始化对象中的属性。例如：

class Dto {
    private Link link;
    private Embedded embedded;
    //constructor,getters and setters...
}

class Link {
    //by default these will be empty instead of null
    private List<Product> products = new ArrayList<>();
    private List<Package> packages = new ArrayList<>();
    //constructor,getters and setters...
}

确保您的类没有使用此注释 @JsonInclude(JsonInclude.Include.NON_NULL) 扩展另一个类。示例：

//It tells Jackson to exclude any property with null values from being serialized
@JsonInclude(JsonInclude.Include.NON_NULL)
class BaseClass {
}

//Any property with null value will follow the rules stated in BaseClass
class Dto extends BaseClass {
    private Link link;
    private Embedded embedded;
    //constructor,getters and setters...
}

class Link extends BaseClass {
   /* rest of the design */
}

如果你有后者并且你不能编辑 BaseClass 那么你可以在特定的类中定义不同的规则：

class Link extends BaseClass{

    //no matter what rules are defined elsewhere,this field will be serialized
    @JsonInclude(JsonInclude.Include.ALWAYS)
    private List<Product> products;
    //same here
    @JsonInclude(JsonInclude.Include.ALWAYS)
    private List<Package> packages;
    //constructor,getters and setters...
}