如何解决用于读取网页源代码并使用 PHP 从标签中获取属性的 PHP 代码
我想使用 PHP 从 HTML 源中获取特定属性。代码是:
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我要找的属性是:
https://video-downloads.googleusercontent.com/AGQNM9JyHNORKCXPqKKQxQYw8RyoSY22v8mitUIUSJvu5jdnmbwSVDnSL8CeUCyndvDN_BJgIYZJbcIOYiwCbL1075AAlmsBTaiuz3_bfvlqDYmetmBjSZROeZQsII0LpkuOyJJNvVnXbdH0nIGT2QFW1kD_DhKqUFApioZIRTtkQ6o1jPj3y9qvruu_pJvh5HZZJ2OZaiKUTof0kX7WAhBGnJ92zUG8vhQ_EobM3mibLANt7QKQWRw
我想知道如何使用 PHP 从上面的 HTML 源代码中获取此代码。就像如何从 PHP 中的 URL 回显 HTML 源中的这个特定属性一样。希望我不要要求太多。任何帮助将非常感激。提前致谢!
解决方法
要从 URL 获取源,请使用 https://www.php.net/manual/en/function.file.php,这将从特定页面获取源。
然后使用 https://www.php.net/preg_match/ 匹配您要使用正则表达式提取的确切文本。
<?php
$htmlCode = file_get_contents('YOUR WEBSITE URL HERE');
preg_match_all('/(https:\/\/video-downloads\.googleusercontent\.com\/.*\")/',$htmlCode,$output_array);
var_dump($output_array); // You can access the output here
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