分数较低的成绩计算器方程式

如何解决分数较低的成绩计算器方程式

我正在尝试创建一个计算器，当您输入积分时，您在课堂上获得的积分总数很多，而我目前正在研究字母的等级，百分比和数量。您需要升入下一年级的分数。 例如95/100

95％

所需积分= 5

我想对需要的点做同样的事情，但要相反。因此，对于同一示例，

损失的积分= 5

如果有帮助，我目前有当前“需要的分数”脚本，但我真的无法弄清楚这一点，幸运的是，对于学校项目而言，并不是一个单独项目，因此我可以学习如何编码

这是所需积分的代码

        var pointsNeeded = totalGrade.value - grade.value; 
            if (gradePercentage > 100) {
                pointsNeeded = pointsNeeded * -1; 
                document.getElementById("pointsNeeded").innerHTML = "You can lose " + pointsNeeded + " point(s) and still have 100%"; 
            }
            else {
                document.getElementById("pointsNeeded").innerHTML = pointsNeeded; 
            }
    }
    else if (gradePercentage < 89,gradePercentage > 79) {
        var pointsNeeded = Math.round(10 * ((totalGrade.value * 0.9) -               
        grade.value)) / 10; 
        document.getElementById("pointsNeeded").innerHTML = pointsNeeded; 
    }
    else if (gradePercentage < 79,gradePercentage > 69) {
        var pointsNeeded = Math.round(10 * ((totalGrade.value * 0.8) -               
        grade.value)) / 10; 
        document.getElementById("pointsNeeded").innerHTML = pointsNeeded; 
    }
    else if (gradePercentage < 69,gradePercentage > 59) {
        var pointsNeeded = Math.round(10 * ((totalGrade.value * 0.7) -               
        grade.value)) / 10; 
        document.getElementById("pointsNeeded").innerHTML = pointsNeeded; 
    }
    else if (gradePercentage < 59) {
        var pointsNeeded = Math.round(10 * ((totalGrade.value * 0.6) -              
        grade.value)) / 10; 
        document.getElementById("pointsNeeded").innerHTML = pointsNeeded; 
    }

gradePercentage是实际百分比，totalGrade是完整成绩，而grade是您拥有的成绩。

这些也是成绩值，

        var gradeLetter = "A"
            document.getElementById("result").innerHTML = gradeLetter +                    " " + result + "%";          
    }
    if (gradePercentage > 79.9,gradePercentage < 90) {
        var gradeLetter = "B"
            document.getElementById("result").innerHTML = gradeLetter +                    " " + result + "%";
    }
    if (gradePercentage > 69.9,gradePercentage < 80) {
        var gradeLetter = "C"
            document.getElementById("result").innerHTML = gradeLetter +                    " " + result + "%";
    }
    if (gradePercentage > 59.9,gradePercentage < 70) {
        var gradeLetter = "D"
            document.getElementById("result").innerHTML = gradeLetter +                    " " + result + "%";          
    }
    if (gradePercentage < 59.9) {
        var gradeLetter = "F"
            document.getElementById("result").innerHTML = gradeLetter +                    " " + result + "%";  
    }   

解决方法

这段代码很不言自明：

let startingPoints = 952.3 // How many points you got on the test
let maxPoints = 1049 // Max possible points you could have gotten

// Your grade (0-100%):
let gradePercentage = 100 * startingPoints / maxPoints; // E.g. 90.7816968541468

// How much less you'd need (as a percentage) to get the next lowest grade:

let extraPercentage = ( gradePercentage % 10 ) + 0.01; // E.g. 0.7916968541468015

// Your new grade (as a percentage) if you bumped it down:
let newGrade = gradePercentage - extraPercentage; // E.g. 89.99

// How many points you'd have to reduce your score by to bump it down to the next lowest 
let extraPoints = ( extraPercentage / 100 * maxPoints ) // E.g. 8.304899999999947

// What your score would be if you bumped it down to the next level:
let newExtraPoints = startingPoints - extraPoints; // E.g. 943.9951

console.log( `Your grade is ${gradePercentage}% (${startingPoints} points out of a possible ${maxPoints}). If you subtract ${extraPercentage}% (or ${extraPoints} points),your grade will be ${newGrade}% (${newExtraPoints} points)` );

唯一的棘手之处是我们要添加0.01，从技术上讲，它可以是0.001或0.0001，或者...好吧，我们必须添加 something 使其低于限制，并且没有设置“正确”的数量，我选择0.01是因为效果很好。

示例输出：

Your grade is 90.7816968541468% (952.3 points out of a possible 1049).
If you subtract 0.7916968541468015% (or 8.304899999999947 points),your grade will be 89.99% (943.9951 points)