如何处理语法错误？

如何解决如何处理语法错误？

对于我正在做的程序，它会通过调查风格的问题并生成一个CSV文件来存储动漫推荐列表，该CSV文件存储有关动漫的信息（例如流派）。

但是，在运行程序时，我想测试在执行问题时是否会出现语法错误，并在完成所有问题后最终显示错误。我希望它能做的是当输入错误时会弹出语法错误。

这是我所做的：

if adventure == 'yes':
   with open("AnimeGenre3.csv",'r',newline='') as f:
       for row in csv.reader(f):
            if row[4] == 'yes':
               anime = str(row[1])
               looping = False
               if anime not in anime_list:
                  anime_list.append(anime)

else:
    print('''
There seems to be a problem in one of the questions
    ''')

让我们说“你喜欢动漫”，然后输入6，则会弹出语法错误提示并重做该问题。但是，在完成所有问题并生成动漫列表之后，便会弹出该列表。

另一个问题是，在完成问题并打印推荐的动画后，如何再次启动程序。它询问您是否要重新开始，但最终却不这样做。这就是我所做的。

StartAgain = str(input('Do you like to start again; yes or no: '))

if StartAgain == 'yes':
     print('''
Let's begin ''')
break
if StartAgain == 'no':
      print('thank you for coming')

else:
  print('''
 Sorry Man got to do it again''')

 # an if statement if the user wants to start again
 # this should rerun the program.

现在，这是我到目前为止已完成的完整程序，老实说，需要找到一种使它更简单的方法，希望我的注释足够好。

 import csv
 anime_list = []
 #in the csv AnimeGenre3.csv it contains information such as the animes,the number of 
 episodes and genres

#printing information about the program.
#has an if statement to identify if it user wants to start the program.

looping1 = True
looping2 = True

print('This is a program that identifies specific anime for you')

while looping1 == True:
begin = str(input('Do you like to start; yes or no: '))

if begin == 'yes':
    print('''
Let's begin
''')
    break
if begin == 'no':
    print('thank you for coming')
else:
    print('''
Sorry Man got to do it again
        ''')
#this section is where the program ask the user questions from there
# it will identify,the genres the user is interested in.

while looping2 == True:

action = str(input('Do you like action; yes or no: '))
adventure = str(input('Do you like adventure; yes or no: '))
print('')
print('recommended anime')
#having to use if statements to find any anime that either say "yes" in the CSV file
# it sorts out all of the sorts that the user said yes to.
# It goes through the rows to identify all of the user genres that say yes
# it should print out the recommend anime
# this prints out a long list of anime

if action == 'yes':
    with open("AnimeGenre3.csv",newline='') as f:
        for row in csv.reader(f):
            if row[3] == 'yes':
                anime = str(row[1])
                looping = False
                if anime not in anime_list:
                    anime_list.append(anime)
                    
if adventure == 'yes':
    with open("AnimeGenre3.csv",newline='') as f:
        for row in csv.reader(f):
            if row[4] == 'yes':
                anime = str(row[1])
                looping = False
                if anime not in anime_list:
                    anime_list.append(anime)

else:
    print('''
There seems to be a problem in one of the questions
        ''')
# if there is a syntax error within the program,it should pop up to the user saying this
    
print(anime_list)

StartAgain = str(input('Do you like to start again; yes or no: '))

if StartAgain == 'yes':
    print('''
Let's begin ''')
    break
if StartAgain == 'no':
    print('thank you for coming')

else:
    print('''
Sorry Man got to do it again''')

# an if statement if the user wants to start again
# this should rerun the program.

解决方法

关于再次开始，您唯一的代码将打印一条语句。它不重复功能。您可能需要考虑更多地调制（组织）程序，以便在再次启动时可以调用一个功能。例如，

def main()
      //this contains your overall logic,starting/ending the program and/or repeating it
     // at some point in time,you call animeselector() to start,and if it needs repeating,you call it again

 def animeselector ()
      //this controls the in/out and selection process

就确保输入格式正确而言，这可能是另一个功能。它可以仅检查答案是“是”还是“否”，否则，请更改变量（例如badanswer == false变为true）。然后，这会在您需要时触发其他操作（重做）。

我建议您阅读“学习Python困难方式”（后面的章节）以进行功能组织，并且一些PyGame教程也有助于了解如何更好地调制程序（因为制作游戏，您需要一个整体功能来完成）。运行游戏，然后再运行一些较小的功能来处理游戏中的活动）。