ARM中的字符串长度？

如何解决ARM中的字符串长度？

试图学习一些基本的ARM，我试图弄清楚如何使用while循环来获取字符串的长度。以下是我试图在C中实现的目标，也是我试图在ARM中实现的目标。我的问题来自while循环，直到击中null终止符并使用变量跟踪它，我才能遍历该字符串。

        char inputString[7];
        
        int lengthOfInput = 0;

        while (inputString[lengthOfInput] != '\0') 
        {
            lengthOfInput++;
        }

---

    .section .data
    
    #need to include \n if you want to test the output. no idea why
    
    input_prompt    :   .asciz "string: "
    input_spec      :   .asciz  "%[^\n]"
    length_spec     :   .asciz  "length: %d\n" 

    
    #8 bytes for 7 characters plus \0
    input: .space 8
    
    .section .text
    
    .global main
    
    main:
    
        #print prompt
        ldr x0,=input_prompt
        bl printf
        
        #get input
        ldr x0,=input_spec
        ldr x1,=input
        bl scanf
        
        #call get_length
        ldr x9,=input
        ldrsw x0,[x9]
        bl get_length
    
        #print result from get_length
        #to do
    
    
        #exit
        b exit
    
    get_length:
        
        #intializing "i" as 0
        add x19,xzr,xzr
    
        get_length_loop:
            
            #address of userString[i]
            add x12,x19,x1
            #if == 0,go somewhere,maybe get_length should be changed
            cbz x12,get_length
            add x19,1
            b get_length_loop
        
        #return result
        mov x0,x19
        ret
    
    exit:
        mov x0,0
        mov x8,93
        svc 0
        ret