基于10天筛选器生成SQL序列号Row_Numbers

分类：编程问答

如何解决基于10天筛选器生成SQL序列号Row_Numbers

Customer_Id        Call_Date             Agent_M_Code    Row_Indicator
 810471698    2020-03-19 13:25:24.910       rmanzan2           1
 810471698    2020-03-22 20:28:19.067       pmaclair           2
 810471698    2020-03-24 09:22:47.833       njeanle            3
 810471698    2020-03-24 12:36:29.367       edelaro4           4
 810471698    2020-03-29 22:36:29.762       kdularo7           1
 810471698    2020-04-11 11:21:11.243       rbustam1           1
 810471698    2020-04-11 17:50:41.023       frenteri           2
 810471698    2020-05-10 11:16:21.683       cschuch2           1
 810471698    2020-05-13 15:26:40.660       gledesma           2
 810471698    2020-07-03 11:26:20.697       cmataver           1
 810471698    2020-07-22 14:19:53.450       irodri13           1
 980471627    2020-07-21 14:00:45.923       jgalind8           1
 980471627    2020-07-21 14:04:42.277       jabne              2
 980471627    2020-07-21 14:06:33.627       abyerley           3
 980471627    2020-07-10 07:11:31.817       rbustam1           1
 980471627    2020-03-15 22:36:29.763       cmanalot           1
 966615610    2020-06-18 17:50:41.023       lmendiza           1
 966615610    2020-06-22 14:19:53.450       melli17            2
 966615610    2020-01-03 11:16:21.683       gledesma           1
 966615610    2020-01-07 15:26:40.660       vchapa1            2
 966615610    2020-01-21 11:26:20.697       amanriq1           1

对于上表，我需要基于customer_Id生成row_indicators，但这里的条件是...如果上方Call_Date和下方call_Date在10天之间，则我们需要按顺序生成row_indicator，即（1， 2,3,4 ..）如果不是这样，我们需要从1开始。

我尝试使用LEAD（）函数，并通过Customer_Id生成了row_number（）分区，但是没有成功。

例如： 在上面的示例表中，前四行在10天之间（小于或等于240小时），然后对于前四行，row_indicators为1,2,4，从第五行开始，Call_Date从1，因为第五行日期不在10天Call_Date范围内。

任何帮助我使用T-SQL脚本的人。

解决方法

您需要使用递归查询：

with 
    data (select t.*,row_number() over(partition by customer_id order by call_date) rn,cte as (
        select d.*,call_date ref_call_date
        from data
        where rn = 1
        union all
        select d.*,case when d.call_date > dateadd(day,10,c.ref_call_date) then d.call_date else c.ref_call_date end
        from cte c
        inner join data d on d.customer_id = c.customer_id and d.rn = c.rn + 1
    )
select 
    c.*,row_number() over(partition by customer_id,ref_call_date order by call_date) new_row_indicator  
from cte c

Demo on DB Fiddle 

Customer_Id | Call_Date               | Agent_M_Code | Row_Indicator | rn | ref_call_date           | new_row_indicator
----------: | :---------------------- | :----------- | ------------: | -: | :---------------------- | ----------------:
  966615610 | 2020-01-03 11:16:21.683 | gledesma     |             1 |  1 | 2020-01-03 11:16:21.683 |                 1
  966615610 | 2020-01-07 15:26:40.660 | vchapa1      |             2 |  2 | 2020-01-03 11:16:21.683 |                 2
  966615610 | 2020-01-21 11:26:20.697 | amanriq1     |             1 |  3 | 2020-01-21 11:26:20.697 |                 1
  980471627 | 2020-03-15 22:36:29.763 | cmanalot     |             1 |  1 | 2020-03-15 22:36:29.763 |                 1
  810471698 | 2020-03-19 13:25:24.910 | rmanzan2     |             1 |  1 | 2020-03-19 13:25:24.910 |                 1
  810471698 | 2020-03-22 20:28:19.067 | pmaclair     |             2 |  2 | 2020-03-19 13:25:24.910 |                 2
  810471698 | 2020-03-24 09:22:47.833 | njeanle      |             3 |  3 | 2020-03-19 13:25:24.910 |                 3
  810471698 | 2020-03-24 12:36:29.367 | edelaro4     |             4 |  4 | 2020-03-19 13:25:24.910 |                 4
  810471698 | 2020-03-29 22:36:29.763 | kdularo7     |             1 |  5 | 2020-03-29 22:36:29.763 |                 1
  810471698 | 2020-04-11 11:21:11.243 | rbustam1     |             1 |  6 | 2020-04-11 11:21:11.243 |                 1
  810471698 | 2020-04-11 17:50:41.023 | frenteri     |             2 |  7 | 2020-04-11 11:21:11.243 |                 2
  810471698 | 2020-05-10 11:16:21.683 | cschuch2     |             1 |  8 | 2020-05-10 11:16:21.683 |                 1
  810471698 | 2020-05-13 15:26:40.660 | gledesma     |             2 |  9 | 2020-05-10 11:16:21.683 |                 2
  966615610 | 2020-06-18 17:50:41.023 | lmendiza     |             1 |  4 | 2020-06-18 17:50:41.023 |                 1
  966615610 | 2020-06-22 14:19:53.450 | melli17      |             2 |  5 | 2020-06-18 17:50:41.023 |                 2
  810471698 | 2020-07-03 11:26:20.697 | cmataver     |             1 | 10 | 2020-07-03 11:26:20.697 |                 1
  980471627 | 2020-07-10 07:11:31.817 | rbustam1     |             1 |  2 | 2020-07-10 07:11:31.817 |                 1
  980471627 | 2020-07-21 14:00:45.923 | jgalind8     |             1 |  3 | 2020-07-21 14:00:45.923 |                 1
  980471627 | 2020-07-21 14:04:42.277 | jabne        |             2 |  4 | 2020-07-21 14:00:45.923 |                 2
  980471627 | 2020-07-21 14:06:33.627 | abyerley     |             3 |  5 | 2020-07-21 14:00:45.923 |                 3
  810471698 | 2020-07-22 14:19:53.450 | irodri13     |             1 | 11 | 2020-07-22 14:19:53.450 |                 1
,

可以使用最早的通话日期和通话日期之间的日期差的整数除法来进行递归操作。

数据（不完整）

drop table if exists #call_data;
go
select * INTO #call_data from (values 
('810471698','2020-03-19 13:25:24.910','rmanzan2'),('810471698','2020-03-22 20:28:19.067','2020-03-24 09:22:47.833','2020-03-24 12:36:29.367','2020-03-29 22:36:29.762','2020-04-11 11:21:11.243',('980471627','2020-07-21 14:00:45.923','2020-07-21 14:04:42.277','2020-07-21 14:06:33.627',('966615610','2020-06-18 17:50:41.023','2020-01-21 11:26:20.697','rmanzan2')) V(customer_id,call_date,Agent_M_Code);

查询

;with
rn_cte(customer_id,Agent_M_Code,rn) as (
    select *,row_number() over(partition by customer_id order by call_date) rn
    from #call_data),grp_cte(customer_id,day_diff_grp) as (
    select cd.customer_id,cd.call_date,cd.Agent_M_Code,datediff(d,rn.call_date,cd.call_date)/10
    from #call_data cd
         left join rn_cte rn on cd.customer_id=rn.customer_id
    where rn.rn=1)
select *,row_number() over (partition by customer_id,day_diff_grp order by call_date) row_indicator
from grp_cte
order by 1,2;

输出

customer_id call_date   Agent_M_Code    day_diff_grp    row_indicator
810471698   2020-03-19 13:25:24.910 rmanzan2    0   1
810471698   2020-03-22 20:28:19.067 rmanzan2    0   2
810471698   2020-03-24 09:22:47.833 rmanzan2    0   3
810471698   2020-03-24 12:36:29.367 rmanzan2    0   4
810471698   2020-03-29 22:36:29.762 rmanzan2    1   1
810471698   2020-04-11 11:21:11.243 rmanzan2    2   1
966615610   2020-01-21 11:26:20.697 rmanzan2    0   1
966615610   2020-06-18 17:50:41.023 rmanzan2    14  1
980471627   2020-07-21 14:00:45.923 rmanzan2    0   1
980471627   2020-07-21 14:04:42.277 rmanzan2    0   2
980471627   2020-07-21 14:06:33.627 rmanzan2    0   3

[EDIT]将代码更改为2天滚动窗口：

;with
rn_cte(customer_id,cd.call_date)/2
    from #call_data cd
         left join rn_cte rn on cd.customer_id=rn.customer_id
    where rn.rn=1)
select *,2;

输出

customer_id call_date   Agent_M_Code    day_diff_grp    row_indicator
810471698   2020-03-19 13:25:24.910 rmanzan2    0   1
810471698   2020-03-22 20:28:19.067 rmanzan2    1   1
810471698   2020-03-24 09:22:47.833 rmanzan2    2   1
810471698   2020-03-24 12:36:29.367 rmanzan2    2   2
810471698   2020-03-29 22:36:29.762 rmanzan2    5   1
810471698   2020-04-11 11:21:11.243 rmanzan2    11  1
966615610   2020-01-21 11:26:20.697 rmanzan2    0   1
966615610   2020-06-18 17:50:41.023 rmanzan2    74  1
980471627   2020-07-21 14:00:45.923 rmanzan2    0   1
980471627   2020-07-21 14:04:42.277 rmanzan2    0   2
980471627   2020-07-21 14:06:33.627 rmanzan2    0   3

[EDIT]更改为240小时滚动窗口

;with
rn_cte(customer_id,datediff(hour,cd.call_date)/240
    from #call_data cd
         left join rn_cte rn on cd.customer_id=rn.customer_id
    where rn.rn=1)
select *,2;

输出

customer_id call_date   Agent_M_Code    day_diff_grp    row_indicator
810471698   2020-03-19 13:25:24.910 rmanzan2    0   1
810471698   2020-03-22 20:28:19.067 rmanzan2    0   2
810471698   2020-03-24 09:22:47.833 rmanzan2    0   3
810471698   2020-03-24 12:36:29.367 rmanzan2    0   4
810471698   2020-03-29 22:36:29.762 rmanzan2    1   1
810471698   2020-04-11 11:21:11.243 rmanzan2    2   1
966615610   2020-01-21 11:26:20.697 rmanzan2    0   1
966615610   2020-06-18 17:50:41.023 rmanzan2    14  1
980471627   2020-07-21 14:00:45.923 rmanzan2    0   1
980471627   2020-07-21 14:04:42.277 rmanzan2    0   2
980471627   2020-07-21 14:06:33.627 rmanzan2    0   3

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