如何解决如何使用Plotly绘制多个图,其中每个图都针对不同的第二天? 已更新
我想按天分别绘制机器观测数据,
因此,可以按小时查看电流,温度等之间的变化。
基本上,我每天要一个地块。问题是,当我使这些Jupyter Notebook过多时,它们无法显示其中的每一个,并密谋给出错误。
f_day->第一天
n_day->第二天
我考虑过使用带有共享y轴的sub_plots,但是我不知道如何在x轴上放置不同的日期
如何使用图形对象和sub_plots进行制作?因此,因此仅使用一个图形对象,这样绘图就不会崩溃。
数据看起来像这样
,ID,IOT_ID,DATE,Voltage,Current,Temperature,Noise,Humidity,Vibration,Open,Close
0,9466,5d36edfe125b874a36c6a210,2020-08-06 09:02:00,228.893,4.17,39.9817,73.1167,33.3133,2.05,T,F
1,9467,2020-08-06 09:03:00,228.168,4.13167,40.0317,69.65,33.265,2.03333,F
2,9468,2020-08-06 09:04:00,228.535,4.13,40.11,71.7,33.1717,2.08333,F
3,9469,2020-08-06 09:05:00,228.597,4.14,40.1683,71.95,33.0417,2.0666700000000002,F
4,9470,2020-08-06 09:06:00,228.405,4.13333,40.2317,71.2167,32.9933,2.0,F
显示错误的代码是这个
f_day = pd.Timestamp('2020-08-06 00:00:00')
for day in range(days_between.days):
n_day = f_day + pd.Timedelta('1 days')
fig_df = df[(df["DATE"] >= f_day) & (df["DATE"] <= n_day) & (df["IOT_ID"] == iot_id)]
fig_cn = px.scatter(
fig_df,x="DATE",y="Current",color="Noise",color_continuous_scale= "Sunset",title= ("IoT " + iot_id + " " + str(f_day.date())),range_color= (min_noise,max_noise)
)
f_day = n_day
fig_cn.show()
解决方法
已更新
问题是关于 plotly 而不是 matplotlib 。同样的方法。显然,轴和标题需要一些美化
import pandas as pd
import plotly.subplots
import plotly.express as px
import datetime as dt
import random
df = pd.DataFrame([{"DATE":d,"IOT_ID":random.randint(1,5),"Noise":random.uniform(0,1),"Current":random.uniform(15,25)}
for d in pd.date_range(dt.datetime(2020,9,dt.datetime(2020,4,23,59),freq="15min")])
# get days to plot
days = df["DATE"].dt.floor("D").unique()
# create axis for each day
fig = plotly.subplots.make_subplots(len(days))
iot_id=3
for i,d in enumerate(days):
# filter data and plot ....
mask = (df["DATE"].dt.floor("D")==d)&(df["IOT_ID"]==iot_id)
splt = px.scatter(df.loc[mask],x="DATE",y="Current",color="Noise",color_continuous_scale= "Sunset",title= f"IoT ({iot_id}) Date:{pd.to_datetime(d).strftime('%d %b')}")
# select_traces() returns a generator so turn it into a list and take first one
fig.add_trace(list(splt.select_traces())[0],row=i+1,col=1)
fig.show()
很简单-首先创建要绘制的轴。然后绘图。我模拟了您的数据,因为您没有在问题中提供该数据。
import pandas as pd
import matplotlib.pyplot as plt
import datetime as dt
import random
df = pd.DataFrame([{"DATE":d,freq="15min")])
# get days to plot
days = df["DATE"].dt.floor("D").unique()
# create axis for each day
fig,ax = plt.subplots(len(days),figsize=[20,10],sharey=True,sharex=False,gridspec_kw={"hspace":0.4})
iot_id=3
for i,d in enumerate(days):
# filter data and plot ....
df.loc[(df["DATE"].dt.floor("D")==d)&(df["IOT_ID"]==iot_id),].plot(kind="scatter",ax=ax[i],c="Noise",colormap= "turbo",title=f"IoT ({iot_id}) Date:{pd.to_datetime(d).strftime('%d %b')}")
ax[i].set_xlabel("") # it's in the titles...
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