如何解决如何使用while循环遍历表并创建具有所需值的另一个表
我有两个表:MainTable
和MyTable
。 MyTable具有唯一的ControlNo和ID。我需要根据EffDate
和MainTable
从MyTable
到ID
首先添加ControlNo
。
为此,我需要查看PreviousID
列,然后查看PreviousID
是否在ID
列中,依此类推。
所需的输出应如下所示:
下面是一个通过提供EffDate
值来获取正确的ID
的伪数据的示例。它可以工作,但是如何遍历整个MainTable
,检索ID
和EffDate
到单独的表中,然后将该表连接到MyTable
?
-- function returns PreviousID based on ID
CREATE FUNCTION [dbo].[GetPriorQuoteID](@ID varchar(50))
RETURNS varchar(50)
AS
BEGIN
DECLARE @RetVal varchar(50)
SET @RetVal = NULL
SELECT TOP 1 @RetVal = MainTable.PreviousID
FROM MainTable
WHERE MainTable.ID = @ID
RETURN @RetVal
END
-- create sample table
IF OBJECT_ID('MainTable') IS NOT NULL DROP TABLE MainTable;
select 3333 as ControlNo,'QuoteID3' as ID,'QuoteID2' as PreviousID,'2020-08-25' as EffDate
into MainTable
union all select 2222 as COntrolNo,'QuoteID2','QuoteID1','2019-08-25'
union all select 1111 as COntrolNo,NULL,'2018-08-25'
union all select 7777 as COntrolNo,'QuoteID6','QuoteID5','2020-02-10'
union all select 6666 as COntrolNo,'2019-02-10'
select * from MainTable
DECLARE @PriorQuote varchar(50)
DECLARE @RetVal VARCHAR(50) = ''
DECLARE @ControlNo INT
DECLARE @ID varchar(50) = 'QuoteID3'
SELECT TOP 1 @ControlNo = MainTable.ControlNo FROM MainTable WHERE MainTable.ID = @ID
Set @PriorQuote = @ID
SELECT TOP 1 @PriorQuote = MainTable.ID FROM MainTable WHERE MainTable.ControlNo = @ControlNo
WHILE dbo.GetPriorQuoteID(@PriorQuote) IS NOT NULL AND dbo.GetPriorQuoteID(@PriorQuote)<> @PriorQuote
BEGIN
SET @PriorQuote = dbo.GetPriorQuoteID(@PriorQuote)
END
SELECT TOP 1 @RetVal = CONVERT(VARCHAR(10),MainTable.EffDate,101)
FROM MainTable
WHERE MainTable.ID = @PriorQuote
SELECT @RetVal
-- clean up
drop table MainTable
drop function GetPriorQuoteID
更新:添加虚拟数据表
-- create sample table #MainTable
IF OBJECT_ID('tempdb..#MainTable') IS NOT NULL DROP TABLE #MainTable;
create table #MainTable (ControlNo int,ID varchar(50),PreviousID varchar(50),EffDate date)
insert into #MainTable values
(3333,'QuoteID3','2020-08-25'),(2222,'2019-08-25'),(1111,'2018-08-25'),(7777,'2020-02-10'),(6666,'2019-02-10')
--select * from #MainTable
-- create sample table #MyTable
IF OBJECT_ID('tempdb..#MyTable') IS NOT NULL DROP TABLE #MyTable;
create table #MyTable (ControlNo int,EffDate date)
insert into #MyTable values
(3333,NULL),NULL)
--select * from #MyTable
解决方法
使用如下所示的CTE,您可以获得预期的结果。 See live demo
详细了解递归CTE here
; with cte as
(
select EffDate,ControlNo,ID,Level=1 from MainTable
where PreviousID is NULL
union all
select C.EffDate,M.ControlNo,M.ID,Level=Level+1 from MainTable AS M
join cte as C on C.ID=M.PreviousID
)
select MyTable.*,cte.EffDate from cte join MyTable on Mytable.ID=cte.ID
,
您可以使用递归查询遍历层次结构。
我将从将原始表与主表连接开始,这将路径限制为仅对我们感兴趣的行。然后,您可以向父表递归。最后,我们需要对每个路径的父级进行过滤:top()
和row_number()
对此非常有用。
考虑:
with cte as (
select t.controlno,t.id,m.previousid,m.effdate,1 lvl
from #maintable m
inner join #mytable t on t.controlno = m.controlno and t.id = m.id
union all
select c.controlno,c.id,c.lvl + 1
from cte c
inner join #maintable m on m.id = c.previousid
)
select top(1) with ties controlno,id,effdate
from cte
order by row_number() over(partition by controlno,id order by lvl desc)
controlno | id | effdate --------: | :------- | :--------- 3333 | QuoteID3 | 2018-08-25 7777 | QuoteID6 | 2019-02-10,
您可以为此使用递归CTE:
WITH cte
AS
(
SELECT m.ID,m.PreviousID
FROM MainTable m
JOIN MainTable m2
ON m.previousID = m2.ID
WHERE m2.previousID IS NULL
UNION ALL
SELECT m2.ID,cte.previousID
FROM cte
JOIN MainTable m2
ON m2.previousID = cte.ID
)
SELECT *
FROM cte;
,
下面是提供的表格的CTE方法的工作示例
;with recur_cte(ControlNo,PreviousID,EffDate,HLevel) as (
select mt.ControlNo,cast(null as varchar(100)),mt.PreviousID,mt.EffDate,1
from MainTable mt
where not exists(select 1
from MainTable mt_in
where mt.ID=mt_in.PreviousID)
union all
select rc.ControlNo,rc.ID,rc.HLevel+1
from recur_cte rc
join MainTable mt on rc.PreviousID=mt.ID and rc.EffDate>mt.EffDate)
select * from recur_cte;
结果
ControlNo ID PreviousID EffDate HLevel
3333 NULL QuoteID2 2020-08-25 1
7777 NULL QuoteID5 2020-02-10 1
7777 NULL NULL 2019-02-10 2
3333 NULL QuoteID1 2019-08-25 2
3333 NULL NULL 2018-08-25 3
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。