在日历上循环三遍

如何解决在日历上循环三遍

我在一家紧急医疗服务机构工作，我们的救护车轮班运行。 Shift A从1月1日的07:00开始，一直持续到1月2日的07:00 班次B从1月2日的07:00开始，在1月3日的07:00停止。 Shift C从1月3日的07:00开始，并立即在1月4日的07:00停止。

然后该模式从Shift A运行24小时，Shift B运行24小时，Shift C运行24小时重新开始，然后重复该模式。

使用Python 3.7，如何编写一个循环以使A，B和C运行3次？它需要在24小时内运行，因为我正在对数据进行进一步的统计分析。例如，相对于班次B，班次发生了多少紧急情况。这是我目前拥有的：

#Who:   David
#What:  Generate a text file showing a calendar date with 24 hours with the shift of A,B or C
#When:  02 September 2020
#Where: Python 3.7
#Why:   The goal is to analyze shift patterns

import datetime

with open("c:\\temp\\calendar_shifts.txt","w") as calendar_dates:
    calendar_dates.write("Key,Calendar,Shift" + "\n")
    date = datetime.datetime(2020,1,6,0)
    shift = 'A'
    i = 0
    while (date < datetime.datetime(2020,15,7,0)):
        date += datetime.timedelta(hours = 1)
        i = i + 1
        calendar_dates.write(str(i) + ',' + str(date)+ "," + str(shift) + "\n")

最终结果如下：

Key,Shift
1,2020-01-01 07:00:00,A 
2,2020-01-01 08:00:00,A 
3,2020-01-01 09:00:00,A 
4,2020-01-01 10:00:00,A 
5,2020-01-01 11:00:00,A 
6,2020-01-01 12:00:00,A 
7,2020-01-01 13:00:00,A 
8,2020-01-01 14:00:00,A 
9,2020-01-01 15:00:00,A 
10,2020-01-01 16:00:00,A 
11,2020-01-01 17:00:00,A 
12,2020-01-01 18:00:00,A 
13,2020-01-01 19:00:00,A 
14,2020-01-01 20:00:00,A 
15,2020-01-01 21:00:00,A 
16,2020-01-01 22:00:00,A 
17,2020-01-01 23:00:00,A 
18,2020-01-02 00:00:00,A 
19,2020-01-02 01:00:00,A 
20,2020-01-02 02:00:00,A 
21,2020-01-02 03:00:00,A 
22,2020-01-02 04:00:00,A 
23,2020-01-02 05:00:00,A 
24,2020-01-02 06:00:00,A 
25,2020-01-02 07:00:00,B 
26,2020-01-02 08:00:00,B 
27,2020-01-02 09:00:00,B 
28,2020-01-02 10:00:00,B 
29,2020-01-02 11:00:00,B 
30,2020-01-02 12:00:00,B 
31,2020-01-02 13:00:00,B 
32,2020-01-02 14:00:00,B 
33,2020-01-02 15:00:00,B 
34,2020-01-02 16:00:00,B 
35,2020-01-02 17:00:00,B 
36,2020-01-02 18:00:00,B 
37,2020-01-02 19:00:00,B 
38,2020-01-02 20:00:00,B 
39,2020-01-02 21:00:00,B 
40,2020-01-02 22:00:00,B 
41,2020-01-02 23:00:00,B 
42,2020-01-03 00:00:00,B 
43,2020-01-03 01:00:00,B 
44,2020-01-03 02:00:00,B 
45,2020-01-03 03:00:00,B 
46,2020-01-03 04:00:00,B 
47,2020-01-03 05:00:00,B 
48,2020-01-03 06:00:00,B 
49,2020-01-03 07:00:00,C 
50,2020-01-03 08:00:00,C 
51,2020-01-03 09:00:00,C 
52,2020-01-03 10:00:00,C 
53,2020-01-03 11:00:00,C 
54,2020-01-03 12:00:00,C 
55,2020-01-03 13:00:00,C 
56,2020-01-03 14:00:00,C 
57,2020-01-03 15:00:00,C 
58,2020-01-03 16:00:00,C 
59,2020-01-03 17:00:00,C 
60,2020-01-03 18:00:00,C 
61,2020-01-03 19:00:00,C 
62,2020-01-03 20:00:00,C 
63,2020-01-03 21:00:00,C 
64,2020-01-03 22:00:00,C 
65,2020-01-03 23:00:00,C 
66,2020-01-04 00:00:00,C 
67,2020-01-04 01:00:00,C 
68,2020-01-04 02:00:00,C 
69,2020-01-04 03:00:00,C 
70,2020-01-04 04:00:00,C 
71,2020-01-04 05:00:00,C 
72,2020-01-04 06:00:00,C 
73,2020-01-04 07:00:00,A 
74,2020-01-04 08:00:00,A 
75,2020-01-04 09:00:00,A 
76,2020-01-04 10:00:00,A 
etc.

解决方法

执行此操作的一种方法是制作一个移位名称数组，然后每24小时使用模算术将移位更改为数组中的下一个条目，以使数组索引保持在范围内：

import datetime

print("Key,Calendar,Shift" + "\n")
date = datetime.datetime(2020,1,6,0)
shifts = ['A','B','C']
num_shifts = len(shifts)
shift = -1   # so that the first increment takes us to the first shift
i = 0
while (date < datetime.datetime(2020,15,7,0)):
    date += datetime.timedelta(hours = 1)
    if i % 24 == 0:
        shift = (shift + 1) % num_shifts
    i = i + 1
    print(str(i) + ',' + str(date)+ "," + str(shifts[shift]) + "\n")

输出：

Key,Shift
1,2020-01-01 07:00:00,A
2,2020-01-01 08:00:00,A
3,2020-01-01 09:00:00,A
4,2020-01-01 10:00:00,A
...
23,2020-01-02 05:00:00,A
24,2020-01-02 06:00:00,A
25,2020-01-02 07:00:00,B
26,2020-01-02 08:00:00,B
...
48,2020-01-03 06:00:00,B
49,2020-01-03 07:00:00,C
...
71,2020-01-04 05:00:00,C
72,2020-01-04 06:00:00,C
73,2020-01-04 07:00:00,A
74,2020-01-04 08:00:00,A

谢谢尼克。这有很大帮助。另外要注意的是，我尝试了以下操作，但无法使其循环多次。

with open("c:\\temp\\x.txt","w") as calendar_dates:
    calendar_dates.write("Key,Shift" + "\n")
    date = datetime.datetime(2020,0)

    x = 0
    i = 0
    j = 0
    k = 0

    while (date < datetime.datetime(2020,3,0)):
        while (i < 24):
            shift = 'A'
            i = i + 1
            date += datetime.timedelta(hours = 1)
            x = x + 1
            calendar_dates.write(str(x) + '," + str(shift) + "\n")
        while (j < 24):
            shift = 'B'
            j = j + 1
            date += datetime.timedelta(hours = 1)
            x = x + 1
            calendar_dates.write(str(x) + '," + str(shift) + "\n")
        while (k < 24):
            shift = 'C'
            k = k + 1
            date += datetime.timedelta(hours = 1)
            x = x + 1
            calendar_dates.write(str(x) + '," + str(shift) + "\n")

在日历上循环三遍

如何解决在日历上循环三遍

解决方法

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