来自C的SQLite多插入只是添加了第一个

我有以下sqlite代码：

std::vector<std::vector<std::string> > InternalDatabaseManager::query(std::string query)
{
    sqlite3_stmt *statement;
    std::vector<std::vector<std::string> > results;

    if(sqlite3_prepare_v2(internalDbManager, query.c_str(), -1, &statement, 0) == sqlITE_OK)
    {
        int cols = sqlite3_column_count(statement);
        int result = 0;
        while(true)
        {
            result = sqlite3_step(statement);

            std::vector<std::string> values;
            if(result == sqlITE_ROW)
            {
                for(int col = 0; col < cols; coL++)
                {
                    std::string s;
                    char *ptr = (char*)sqlite3_column_text(statement, col);
                    if(ptr) s = ptr;

                    values.push_back(s);
                }
                results.push_back(values);
            } else
            {
                break;
            }
        }

        sqlite3_finalize(statement);
    }

    std::string error = sqlite3_errmsg(internalDbManager);
    if(error != "not an error") std::cout << query << " " << error << std::endl;

    return results;
}

当我尝试传递查询字符串时：

INSERT INTO cpuUsage (NODE_ID, TIME_ID, CORE_ID, USER, NICE, SYSMODE, IDLE, IOWAIT, IRQ, SOFTIRQ, Steal, GUEST) VALUES (1, 1, -1, 1014711, 117915, 175551, 5908257, 112996, 2613, 4359, 0, 0); INSERT INTO cpuUsage (NODE_ID, TIME_ID, CORE_ID, USER, NICE, SYSMODE, IDLE, IOWAIT, IRQ, SOFTIRQ, Steal, GUEST) VALUES (1, 1, 0, 1014711, 117915, 175551, 5908257, 112996, 2613, 4359, 0, 0); INSERT INTO cpuUsage (NODE_ID, TIME_ID, CORE_ID, USER, NICE, SYSMODE, IDLE, IOWAIT, IRQ, SOFTIRQ, Steal, GUEST) VALUES (1, 1, 1, 1014711, 117915, 175551, 5908257, 112996, 2613, 4359, 0, 0);

它只会插入第一个插入.使用其他一些工具精简版sqliteStudio它可以正常运行.

有什么想法可以帮助我吗？

谢谢,

佩德罗

编辑

我的查询是一个std :: string.

const char** pzTail;
const char* q = query.c_str();

int result = -1;
do {
    result = sqlite3_prepare_v2(internalDbManager, q, -1, &statement, pzTail);
    q = *pzTail;
}
while(result == sqlITE_OK);

这给了我描述：无法将’const char *’转换为’const char **’以将参数’5’转换为’int sqlite3_prepare_v2(sqlite3 *,const char *,int,sqlite3_stmt *,const char *)’

解决方法:

sqlite的prepare_v2只会从字符串中的第一个插入创建一个语句.您可以将其视为“流行前沿”机制.

int sqlite3_prepare_v2(
  sqlite3 *db,            /* Database handle */
  const char *zsql,       /* sql statement, UTF-8 encoded */
  int nByte,              /* Maximum length of zsql in bytes. */
  sqlite3_stmt **ppStmt,  /* OUT: Statement handle */
  const char **pzTail     /* OUT: Pointer to unused portion of zsql */
);

从http://www.sqlite.org/c3ref/prepare.html起

If pzTail is not NULL then *pzTail is made to point to the first byte
past the end of the first sql statement in zsql. These routines only
compile the first statement in zsql, so *pzTail is left pointing to
what remains uncompiled.

pzTail参数将指向其余插入,因此您可以遍历所有插入,直到它们都已准备好.

另一种选择是一次只进行一次插入,这使得其余的处理代码通常更简单一些.

通常情况下,我看到人们会在相同的交易下对他们进行评估.但事实并非如此.第二个可能会失败,第一个和第三个仍然会成功.

来自C的SQLite多插入只是添加了第一个

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